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P1 Effective Vulnerable Function Identification based on CVE Description Empowered by Large Language Models

基于大语言模型赋能CVE描述的有效漏洞函数识别
ASE Proceedings of the 39th IEEE/ACM International Conference on Automated Software Engineering2024匹配度 5/10 · 该论文利用LLM从CVE描述中识别漏洞根因函数,属于AI→PL中利用LLM改进程序分析(漏洞分析)的范畴,与用户关注的LLM/Agent改进静态分析有部分交集;但研究目标聚焦安全领域的漏洞定位,而非静态分析/形式化验证的核心问题,且未涉及浮点或贝叶斯程序分析,因此匹配度中等。引用 10 inbox
Yulun Wu, Ming Wen, Zeliang Yu, Xiaochen Guo, Hai Jin
crossref: 2026-09-12

AI 速览

一句话:提出利用大语言模型从CVE描述中识别漏洞根因所在函数,以支持漏洞可达性分析与复现等下游任务。

开源软件促进了代码复用,但公开漏洞数量激增,给下游用户带来严重安全风险。漏洞可达性分析与漏洞复现等任务的关键是识别漏洞根因所在的易受攻击函数;然而公开漏洞数据集(如NVD)通常不包含该信息,精确定位漏洞函数仍是长期挑战。论文提出基于CVE描述、由大语言模型赋能的有效漏洞函数识别方法。给出的摘要主要阐述问题背景与挑战,未展开具体模型设计、训练或推理流程及实验评估;因此其核心方法细节与关键结果仍需参见论文正文。

问题
公开漏洞数据集(如NVD)很少记录漏洞根因所在的函数,而漏洞可达性分析和复现等下游任务又依赖精确定位该易受攻击函数。
方法
根据标题,方法以CVE描述为输入、以大语言模型为核心来识别漏洞函数;所给摘要未描述具体技术路线。
评估
所给摘要未提供评估方式、数据集或实验结果。
原文摘要(Abstract)

Open-source software (OSS) has profoundly transformed the software development paradigm by facilitating effortless code reuse. However, in recent years, there has been an alarming increase in disclosed vulnerabilities within OSS, posing significant security risks to downstream users. Therefore, analyzing existing vulnerabilities and precisely assessing their threats to downstream applications become pivotal. Plenty of efforts have been made recently towards this problem, such as vulnerability reachability analysis and vulnerability reproduction. The key to these tasks is identifying the vulnerable function (i.e., the function where the root cause of a vulnerability resides). However, public vulnerability datasets (e.g., NVD) rarely include this information as pinpointing the exact vulnerable functions remains to be a longstanding challenge.

链接与引用

DOI 原文 ·

BibTeX
@inproceedings{paperbot8280,
  title = {Effective Vulnerable Function Identification based on CVE Description Empowered by Large Language Models},
  author = {Yulun Wu and Ming Wen and Zeliang Yu and Xiaochen Guo and Hai Jin},
  booktitle = {ASE},
  year = {2024},
  doi = {10.1145/3691620.3695013}
}